Discuss the chemistry of Lassaigne's | Class 11 Chemistry Chapter Organic Chemistry Some Basic Principles and Techniques, Organic Chemistry Some Basic Principles and Techniques NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Organic Chemistry Some Basic Principles and Techniques. This page offers a step-by-step solution to the specific question from Exercise 1, Question 21: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 21:

Discuss the chemistry of Lassaigne's test.

Answer:

Lassaigne's test: This test is used to detect the presence of nitrogen, sulphur, halogens, and phosphorous in an organic compound. These elements are present in covalent form in an organic compound. These are converted into the ionic form by fusing the compound with sodium metal.

The cyanide, sulphide, and halide of sodium formed are extracted from the fused mass by boiling it in distilled water. The extract so obtained is called Lassaigne's extract. This Lassaigne's extract is then tested for the presence of nitrogen, sulphur, halogens, and phosphorous.

 

(a) Test for nitrogen

Lassaignes's extract     +     Ferrous Sulphate

                                           ⬇     Conc. sulphuric acid

                                   Prussian blue colour

                                   (Ferriferro cyanide)

 

Chemistry of the test

In the Lassaigne's test for nitrogen in an organic compound, the sodium fusion extract is boiled with iron (II) sulphate and then acidified with sulphuric acid. In this process, sodium cyanide first reacts with iron (II) sulphate and forms sodium hexacyanoferrate (II). Then, on heating with sulphuric acid, some iron (II) gets oxidised to form iron (III) hexacyanoferrate (II), which is Prussian blue in colour. The chemical equations involved in the reaction can be represented as

6CN  +   Fe2+    →      [Fe(CN)6]4-

3[Fe(CN)6]4-   +    4Fe3+        →    Fe4[Fe(CN)6]3 

                                                     Prussian blue colour

 

(b) Test for sulphur

(i) Lassaignes's extract  +   Lead acetate    →    Black precipitate

Chemistry of the test

In the Lassaigne's test for sulphur in an organic compound, the sodium fusion extract is acidified with acetic acid and then lead acetate is added to it. The precipitation of lead sulphide, which is black in colour, indicates the presence of sulphur in the compound.

S2-  +  Pb2+    →   PbS

                            (Black)

(ii) Lassaignes's extract  +   Sodium nitroprusside   →    Violet colour

 

Chemistry of the test

The sodium fusion extract is treated with sodium nitroprusside. Appearance of violet colour also indicates the presence of sulphur in the compound.

S2-  +  [Fe(CN)5 NO]2-    →    [Fe(CN)5NOS]-4

                                                   (Violet)

If in an organic compound, both nitrogen and sulphur are present, then instead of NaCN, formation of NaSCN takes place.

Na + C + N + S → NaSCN

This NaSCN (sodium thiocyanate) gives a blood red colour. Prussian colour is not formed due to the absence of free cyanide ions.

Fe3+  + SCN   →    [Fe(SCN)]2+

                              (Blood Red)

 

(c) Test for halogens

Chemistry of the test

In the Lassaigne's test for halogens in an organic compound, the sodium fusion extract is acidified with nitric acid and then treated with silver nitrate.

X-   + Ag+    →    AgX

                         (X = Cl,Br,I)

If nitrogen and sulphur both are present in the organic compound, then the Lassaigne's extract is boiled to expel nitrogen and sulphur, which would otherwise interfere in the test for halogens.


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 21: Discuss the chemistry of Lassaigne's test.....