Class 11 Chemistry - Chapter Equilibrium NCERT Solutions | What is the minimum volume of water requ

Welcome to the NCERT Solutions for Class 11th Chemistry - Chapter Equilibrium. This page offers a step-by-step solution to the specific question from Excercise ".$ex_no." , Question 72: what is the minimum volume of water required to di....
Question 72

What is the minimum volume of water required to dissolve 1g of calcium sulphate at 298 K? (For calcium sulphate, Ksp is 9.1 x 10-6).

Answer

CaSO4(s)   ↔   Ca 2+ (aq) + SO2-4(aq)

Ksp   =  [ Ca 2+ ] [ SO2- ]

Let the solubility of CaSO4 be s.

Then, Ksp   = s2

9.1 x 10-6  = s2

s  =  3.02 x 10-3 mol/L

Molecular mass of CaSO4 = 136 g/mol

Solubility of  CaSO4 in gram/L = 3.02 × 10-3 × 136 = 0.41 g/L

This means that we need 1L of water to dissolve 0.41g of CaSO4

Therefore, to dissolve 1g of CaSO4 we require  = 1/0.41 L = 2.44 Lof water.

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