Class 11 Chemistry - Chapter Equilibrium NCERT Solutions | A 0.02 M solution of pyridinium hydrochl

Welcome to the NCERT Solutions for Class 11th Chemistry - Chapter Equilibrium. This page offers a step-by-step solution to the specific question from Exercise 1, Question 62: a 0 02 m solution of pyridinium hydrochloride has....
Question 62

A 0.02 M solution of pyridinium hydrochloride has pH = 3.44. Calculate the ionization constant of pyridine

Answer

Given,  pH  =  3.44

We know that

pH  =  -log [H+]

∴ [H+]  =  3.63x10-4

Then Kh  = ( 3.63x10-4 )2 / 0.02         (∵ Concentration is 0.02M)

⇒ Kh  =  6.6 x 10-6

Now , Kh  =  Kw / Ka

⇒  K=  Kw / Kh

= 10-14 / 6.6 x 10-6

= 1.51 x 10-9

 

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