Class 11 Chemistry Equilibrium: NCERT Solutions for Question 52

This page offers a step-by-step solution to the specific question NCERT Class 11th Chemistry - Equilibrium | what is the ph of 0 001 m aniline solution the io Answer from NCERT Class 11th Chemistry, Chapter Equilibrium.
Question 52

What is the pH of 0.001 M aniline solution? The ionization constant of aniline can be taken from Table 7.7. Calculate the degree of ionization of aniline in the solution. Also calculate the ionization constant of the conjugate acid of aniline.

Answer

Kb  =   4.27 x 10-10

c  =  0.001M

pH  = ?

α  =  ?

Kb  =  cα2

4.27 x 10-10  = 0.001 x α2

4270 x 10-10 = α2

α = 65.34 x 10-4

Then (anion) = cα  = 0.001 x 65.34 x 10-4

= 0.65 x 10-5

pOH = -log ( 0.65 x 10-5)

= 6.187

pH  =  7.813

Now

Ka x Kb = Kw

 ∴ 4.27 x 10-10 x Ka = Kw

Ka  =  10-14 / 4.27 x 10-10

= 2.34 x 10-5

Thus, the ionization constant of the conjugate acid of aniline is 2.34 × 10-5

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