A population grows exponentially if sufficient amounts of food resources are available to the individual. Its exponential growth can be calculated by the following integral form of the exponential growth equation:
Nt = No ert
Where,
Nt= Population density after time t
NO= Population density at time zero
r = Intrinsic rate of natural increase
e = Base of natural logarithms (2.71828)
From the above equation, we can calculate the intrinsic rate of increase (r) of a population.
Now, as per the question,
Present population density = x
Then,
Population density after two years = 2x
t = 3 years
Substituting these values in the formula, we get:
⇒ 2x = x e3r
⇒ 2 = e3r
Applying log on both sides:
⇒ log 2 = 3r log e
Hence, the intrinsic rate of increase for the above illustrated population is 0.2311.
Fill in the blanks:
(a) Humans reproduce __________. (asexually/sexually)
(b) Humans are__________. (oviparous/viviparous/ovoviviparous)
(c) Fertilization is __________ in humans. (external/internal)
(d) Male and female gametes are __________. (diploid/haploid)
(e) Zygote is __________. (diploid/haploid)
(f) The process of release of the ovum from a mature follicle is called__________.
(g) Ovulation is induced by a hormone called the __________.
(h) The fusion of male and female gametes is called _____________.
(i) Fertilisation takes place in _____________.
(j) Zygote divides to form _____________which is implanted in uterus.
(k) The structure which provides vascular connection between fetus and uterus is called ____________.
Explain the following terms with example
(a) Co-dominance
(b) Incomplete dominance
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It's value of e not of loge 0.434 is nothing but value of loge
Sir can u tell me log e value is 2.7 nd log 3 is 0.4 bt here 3 * 0.434 why?
Thanks a lot ð
yupp i did the same...
The ârâis the specific growth rate ( dN/Ndt ) when population growth is exponential. ( Population becomes 2 from 1 in three years. dN= 2, N=1 and dt = 3 ) By putting the values we get 2/ 1x3 = 0.66, it is so simple