Q1 |
Compare the properties of electrons, protons and neutrons. |
Ans: |
Electron:
(I) Electron are available external the core of an atom.
(ii) Electron are contrarily charged.
(iii) The mass of an electron is considered to immaterial.
Proton:
(I) Proton are available in the core of a molecule.
(ii) Proton are emphatically charged.
(iii) The mass of a proton is roughly multiple times as the mass of an electron.
Neutron:
(I) Neutron are available in the core of an atom.
(ii) Neutron are unbiased.
(iii) The mass of neutron is almost equivalent to the mass of a proton. |
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Q2 |
What are the limitations of J.J. Thomson’s model of the atom? |
Ans: |
As per J.J. Thomson's model of a particle, the electrons are implanted all over in the emphatically charged circles. In any case, tests done by different researchers showed that protons are available just in the focal point of the particle and electrons are dispersed around it. |
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Q3 |
What are the limitations of Rutherford’s model of the atom? |
Ans: |
As per Rutherford's model of a molecule the electrons are spinning in a round circle around the core. Any such molecule that spins would go through speed increase and emanate energy. The spinning electron would lose its energy lastly fall into the core, the particle would be profoundly temperamental. In any case, we realize that molecules are very steady. |
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Q4 |
Describe Bohr’s model of the atom. |
Ans: |
Bohr's model of the molecule
(1) Atoms have a nucleus in the middle.
(2) Electrons rotate around the nucleus.
(3) Certain exceptional circles known as discrete circles of electrons are permitted inside the molecule.
(4) While rotating in discrete circles the electrons don't transmit energy.
(5) These circles or shells are called energy levels.
(6) These circles or shells are represented by the letters K, L, M, N or the numbers n = 1, 2, 3, 4
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Q5 |
Compare all the proposed models of an atom given in this chapter. |
Ans: |
Thomson's model : A molecule comprises of an emphatically accused circle of electrons installed in it.
Rutherford's model : An atom comprises of a decidedly charged molecule assembled at the middle known as the nucleus. The size of nucleus exceptionally little when contrasted with the size of the atom. The electron spin around the nucleus in clear cut circles.
Bohr's model : There are just sure circles known as discrete circles inside the atom in which electrons rotate around the nucleus. Electrons don't emanate energy while rotating. |
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Q6 |
Summarise the rules for writing of distribution of electrons in various shells for the first eighteen elements. |
Ans: |
The standards for composing of appropriation of electrons in different shells for the initial eighteen components are:
(I) The most extreme number of electrons present in a shell is given by the formula 2 n2
∵ n = orbit number i.e., 1, 2, 3
∵ Maximum number of electrons in various shells are:
K shell n = 1 2n2 => 2(1)2 = 2
L shell n = 2 2n2 => 2(2)2 = 8
M shell n = 3 2n2 => 2(3)2 = 18
N shell n = 4 2n2 => 2(4)2 = 32
(ii) The most extreme number of electrons that can be obliged in the furthest orbit is 8.
(iii) Electrons are not obliged in a given shell except if the internal shells are filled. |
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Q7 |
Define valency by taking examples of silicon and oxygen. |
Ans: |
Valency is the consolidating limit of a molecule.
Nuclear number of oxygen = 8 Atomic number of silicon = 14 K L M
Electronic configuration of oxygen = 2 6 –
Electronic configuration of silicon =2 8 4
In the molecules of oxygen the valence electrons are 6 (i.e., electrons in the outermost shell). To fill the orbit, 2 electrons are required. In the particle of silicon, the valence electrons are 4. To fill this orbit 4 electrons are required.
Subsequently, the joined limit of oxygen is 2 and of silicon is 4.
i.e., Valency of oxygen = 2
Valency of silicon = 4 |
|
Q8 |
Explain with examples (i) Atomic number, (ii) Mass number, (iii) Isotopes and iv) Isobars. Give any two uses of isotopes. |
Ans: |
(I) Atomic number: The atomic number of a component is equivalent to the quantity of protons in the nucleus of its molecule.
e.g., Oxygen has 6 protons thus atomic no. = 6.
(ii) Mass number: The mass number of a molecule is equivalent to the quantity of protons and neutrons in its nucleus.
Nucleons = number of protons + number of neutrons
Example: Protons + Neutrons = Nucleus = Mass number = 6 + 6 = 12
(iii) Isotopes: Isotopes are molecules of a similar component which have different mass numbers however same atomic number.
(iv) Isobars: Isobars are molecules having similar mass number however different atomic numbers.
Both calcium and argon have a similar mass number yet unique atomic number.
Two uses of isotopes are:
(I) An isotope of iodine is utilized in the treatment of goiter.
(ii) An isotope of uranium is utilized as a fuel in atomic reactors. |
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Q9 |
Na+ has completely filled K and L shells. Explain. |
Ans: |
Sodium atom (Na), has atomic number =11
Number of protons =11
Number of electrons = 11
Electronic configuration of Na = K L M – 2 8 1
Sodium atom (Na) lose 1 electron to get steady and structure Na+ particles. Thus it has totally filled K and L shells. |
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Q11 |
The average atomic mass of a sample of an element X is 16.2 u. What are the percentages of isotopes 168 X and 188 X in the sample? |
Ans: |
Given, the normal atomicr mass of an example of a component X is 16.2u.
Two isotopes of component = and
Presently, Let's percent of isotope be x and percent of be 100 - x
In this way, According to the inquiry,
Average Atomic Mass :
Subsequently the level of isotope is 90 % and the percentage isotope is 10%. |
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Q12 |
If Z = 3, what would be the valency of the element? Also, name the element. |
Ans: |
Z (atomic no.)= 3
∴ Electronic configuration = 2, 1
Valency = 1
Name of the element is lithium. |
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Q13 |
Composition of the nuclei of two atomic species X and Y are given as under
X Y
Protons = 6 6
Neutrons = 6 8
Give the mass numbers of X and Y. What is the relation between the two species? |
Ans: |
Mass number of X = Protons + Neutrons = 6 + 6 = 12
Mass number of Y = Protons + Neutrons = 6 + 8 = 14
As the atomic number is the similar i.e., = 6.
[atomic number = number of protons].
Both X and Y are isotopes of the similar element. |
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Q14 |
For the following statements, write T for True and F for False.
(a) J.J. Thomson proposed that the nucleus of an atom contains only nucleons.
(b) A neutron is formed by an electron and a proton combining together. Therefore, it is neutral.
(c) The mass of an electron is about 1/2000 times that of proton.
(d) An isotope of iodine is used for making tincture iodine, which is used as a medicine.
Put tick (✓) against correct choice and cross (✕) against wrong choice in questions 15, 16 and 17. |
Ans: |
(a) False
(b) False
(c) True
(d) False |
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Q15 |
Rutherford’s alpha-particle scattering experiment was responsible for the discovery of
(a) Atomic Nucleus (b) Electron
(c) Proton (d) Neutron
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Ans: |
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Q16 |
Isotopes of an element have
(a) the same physical properties
(b) different chemical properties
(c) different number of neutrons
(d) different atomic numbers. |
Ans: |
(c) different number of neutrons |
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Q17 |
Number of valence electrons in Cl-ion are:
(a) 16 (b) 8 (c) 17 (d) 18 |
Ans: |
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Q18 |
Which one of the following is a correct electronic configuration of sodium?
(a) 2,8 (b) 8,2,1 (c) 2,1,8 (d) 2,8,1. |
Ans: |
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Q19 |
Complete the following table.
Atomic
Number |
Mass
Number |
Number
of
Neutrons |
Number
of
Protons |
Number
of
Electrons |
Name of
the Atomic
Species |
9 |
- |
10 |
- |
- |
- |
16 |
32 |
- |
- |
- |
Sulphur |
- |
24 |
- |
12 |
- |
- |
- |
2 |
- |
1 |
- |
- |
- |
1 |
0 |
1 |
0 |
- |
|
Ans: |
Atomic
Number |
Mass
Number |
Number
of
Neutrons |
Number
of
Protons |
Number
of
Electrons |
Name of
the Atomic
Species |
9 |
19 |
10 |
9 |
9 |
Fluorine |
16 |
32 |
16 |
16 |
16 |
Sulphur |
12 |
24 |
12 |
12 |
12 |
Magnesium |
1 |
2 |
1 |
1 |
1 |
Hydrogen
Deuterium |
1 |
1 |
0 |
1 |
0 |
Hydrogen |
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