Conic Secrtions Question Answers: NCERT Class 11 Mathematics

Welcome to the Chapter 11 - Conic Secrtions, Class 11 Mathematics - NCERT Solutions page. Here, we provide detailed question answers for Chapter 11 - Conic Secrtions.The page is designed to help students gain a thorough understanding of the concepts related to natural resources, their classification, and sustainable development.

Our solutions explain each answer in a simple and comprehensive way, making it easier for students to grasp key topics and excel in their exams. By going through these Conic Secrtions question answers, you can strengthen your foundation and improve your performance in Class 11 Mathematics. Whether you're revising or preparing for tests, this chapter-wise guide will serve as an invaluable resource.

We are familiar with various concepts of lines, now we have to know about conic section. For various sections of cones like circle, ellipse, parabola, hyperbola etc. we need to go through the details of this chapter. The knowledge which we gain through it has great importance. These figures are related to our real life also like the shape of an egg is elliptical. It will be very interesting to know about them. This chapter has topics such as circle, ellipse, parabola, hyperbola, a point, a straight line, a pair of intersecting lines as a degenerate case of a conic section, standard equations of sections of cone.

Download PDF - Chapter 11 Conic Secrtions - Class 11 Mathematics

Download PDF - NCERT Examplar Solutions - Chapter 11 Conic Secrtions - Class 11 Mathematics

Exercise 1

  • Q1

    Find the equation of the circle with centre (0, 2) and radius 2

    Ans:

    The equation of a circle with centre (hk) and radius is given as

    (x­ – h)2 + (y ­– k)2 = r2

    It is given that centre (hk) = (0, 2) and radius (r) = 2.

    Therefore, the equation of the circle is

    (x – 0)2 + (y – 2)2 = 22

    x2 + y2 + 4 ­– 4 y = 4

    x2 + y2 ­– 4y = 0


    Q2

    Find the equation of the circle with centre (–2, 3) and radius 4

    Ans:

    The equation of a circle with centre (hk) and radius is given as

    (x­ – h)2 + (y ­– k)2 = r2

    It is given that centre (hk) = (–2, 3) and radius (r) = 4.

    Therefore, the equation of the circle is

    (x + 2)2 + (y – 3)2 = (4)2

    x2 + 4x + 4 + y2 – 6y + 9 = 16

    x2 + y2 + 4– 6y – 3 = 0


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