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Academic session 2026-27, Chapter 9 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Physics - Chapter Mechanical Properties of Fluids. This page offers a step-by-step solution to the specific question from Exercise 1, Question 8:
A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cross-section of the piston carrying the load is 425 cm2. What maximum pressure would the smaller piston have to bear?
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cross-section of the piston carrying the load is 425 cm2. What maximum pressure would the smaller piston have to bear?
The maximum mass of a car that can be lifted, m = 3000 kg
Area of cross-section of the load-carrying piston, A = 425 cm2 = 425 × 10-4 m2
The maximum force exerted by the load, F = mg
= 3000 × 9.8 = 29400 N
The maximum pressure exerted on the load-carrying piston, P = F / A
= 29400 / 425 x 10-4
= 6.917 × 105 Pa
Pressure is transmitted equally in all directions in a liquid. Therefore, the maximum pressure that the smaller piston would have to bear is 6.917 × 105 Pa.
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 8: A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cro....
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