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Academic session 2026-27, Chapter 1 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Physics - Chapter Unit and measurment. This page offers a step-by-step solution to the specific question from Exercise 1, Question 15:
A famous relation in physics relates 'moving mass' m to the 'rest mass' m0 of a particle in terms of its speed v and the speed of light, c. (This relation first arose as a consequence of special relativity due to Albert Einstein). A boy recalls the relation almost correctly but forgets where to put the constant c. He writes:
m = m0 / (1-v2)½
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.A famous relation in physics relates 'moving mass' m to the 'rest mass' m0 of a particle in terms of its speed v and the speed of light, c. (This relation first arose as a consequence of special relativity due to Albert Einstein). A boy recalls the relation almost correctly but forgets where to put the constant c. He writes:
m = m0 / (1-v2)½
Given the relation,
m = m0 / (1-v2)½
Dimension of m = M1 L0 T0
Dimension of = M1 L0 T0
Dimension of v = M0 L1 T-1
Dimension of v2 = M0 L2 T-2
Dimension of c = M0 L1 T-1
The given formula will be dimensionally correct only when the dimension of L.H.S is the same as that of R.H.S. This is only possible when the factor, (1-v2)½ is dimensionless i.e., (1 - v2) is dimensionless. This is only possible if v2 is divided by c2. Hence, the correct relation is
m = m0 / (1-v2/c2)½ .
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 15: A famous relation in physics relates 'moving mass' m to the 'rest mass' m0 of a part....
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