Percentage Calculator
Calculate percentage from obtained marks and total marks.
Academic session 2026-27, Chapter 6 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Equilibrium. This page offers a step-by-step solution to the specific question from Exercise 1, Question 53:
Calculate the degree of ionization of 0.05M acetic acid if its pKa value is 4.74.
How is the degree of dissociation affected when its solution also contains (a) 0.01 M (b) 0.1 M in HCl?
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.Calculate the degree of ionization of 0.05M acetic acid if its pKa value is 4.74.
How is the degree of dissociation affected when its solution also contains (a) 0.01 M (b) 0.1 M in HCl?
c = 0.05 M
pKa = 4.74
pKa = -log (Ka)
Ka = 1.82 x 10-5

When HCl is added to the solution, the concentration of H+ ions will increase. Therefore, the equilibrium will shift in the backward direction i.e., dissociation of acetic acid will decrease.
Case I: When 0.01 M HCl is taken.
Let x be the amount of acetic acid dissociated after the addition of HCl.
CH3COOH ↔ H+ + CH3COO-
Initial Conc. 0.05M 0 0
After dissociation 0.05-x 0.01+x x
As the dissociation of a very small amount of acetic acid will take place, the values i.e., 0.05 - x and 0.01 + x can be taken as 0.05 and 0.01 respectively.
Ka = [CH3COO-] [ H+] / [CH3COOH]
∴ Ka = (0.01) (x) / (0.05)
x = 1.82 x 10-5 x(multiply) 0.05 / 0.01
x = 1.82 x 10-3 x(multiply) 0.05
Now
α = Amount of acid dissociated / amount of acid taken
= 1.82 x 10-3 x 0.05 / 0.05
= 1.82 x 10-3
Case II: When 0.1 M HCl is taken.
Let the amount of acetic acid dissociated in this case be X. As we have done in the first case, the concentrations of various species involved in the reaction are:
[CH3COOH] = 0.05 - X : 0.05M
[CH3COO-] = X
[ H+] = 0.1+X ; 0.1M
Ka = [CH3COO-] [ H+] / [CH3COOH]
∴ Ka = (0.1) (X) / (0.05)
x = 1.82 x 10-5 x(multiply) 0.05 / 0.1
x = 1.82 x 10-4 x(multiply) 0.05
Now
α = Amount of acid dissociated / amount of acid taken
= 1.82 x 10-4 x 0.05 / 0.05
= 1.82 x 10-4
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Stay updated with our latest educational content and study tips
All businesses are gathering information on customers, products, employees, and expenditures, and someone must make decisions based on the data. That individual is the data analyst. Unlike many career changers imagine, the job is open to a broader cross-section of the population than a typical career change. A lot of working analysts trained in commerce, … Read more
Read MoreAre often purchased, talked and planned as being a replacement for another. They aren’t. One safeguards your family’s income in your absence and the other safeguards your family’s savings in the event that someone becomes ill. An examination of what they do, what they do not do, and why they are missing it when one … Read more
Read MorePay upfront, or pay off less and over time? The truth depends on four factors most consumers will never compare at the same time: the interest rate on the house loan, the interest rate on the savings account, the rate of home price appreciation, and the cost of renting the home until you actually buy … Read more
Read MoreThirty is when the question starts to get raised and you’re able to do something because you know you have the experience—you know you have the responsibility. Here are some ways to consider the choice based on a realistic assessment without idealizing either aspect. Restlessness is one of those things that appears in your early … Read more
Read MoreCalculate percentage from obtained marks and total marks.
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 53: Calculate the degree of ionization of 0.05M acetic acid if its pKa value is 4.74. How is the degr....
Fresh educational articles and updates.
Most-read articles from SaralStudy.
Fast access to frequently used study resources.
Recently viewed articles based on SaralStudy activity.
Add Comment