Calculate the entropy change in surround | Class 11 Chemistry Chapter Thermodynamics, Thermodynamics NCERT Solutions

Current NCERT chapter

Academic session 2026-27, Chapter 5 in the current curriculum.

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Thermodynamics. This page offers a step-by-step solution to the specific question from Exercise 1, Question 22:

Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard conditions. ΔfH0 = –286 kJ mol–1.

. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 22:

Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard conditions. ΔfH0 = –286 kJ mol–1.

Answer:

It is given that 286 kJ mol-1of heat is evolved on the formation of 1 mol of H2O(l). Thus, an equal amount of heat will be absorbed by the surroundings.

qsurr = +286 kJ mol-1

Entropy change (ΔSsurr) for the surroundings =  qsurr / 7

= 286 kJ mol-1  / 298k

\therefore  ΔSsurr = 959.73 J mol-1K-1


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Thermodynamics.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • safia
  • Mar 13, 2019

in the above qusetion T does not given but in solution how it can be given to solve it


  • Palak
  • Jan 12, 2019

Great


  • ghanshyamsinh
  • Sep 07, 2018

calculate the bond enthalpy of HCl if enthalpy of H and Cl is 424 kj/mol and 230 kj/mol. the enthalpy of formation of HCl is -91 kj/mol


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 22: Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard condit....

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