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Academic session 2026-27, Chapter 2 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Structure of Atom. This page offers a step-by-step solution to the specific question from Exercise 1, Question 47:
Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate
(a) the frequency of emission,
(b) distance traveled by this radiation in 30 s
(c) energy of quantum and
(d) number of quanta present if it produces 2 J of energy.
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate
(a) the frequency of emission,
(b) distance traveled by this radiation in 30 s
(c) energy of quantum and
(d) number of quanta present if it produces 2 J of energy.
λ = 616nm or = 616x10-9m
a) Frequency , v=c/ λ = 3.8x108 / 616x10-9 = 4.87x1014 s-1
b) Velocity of the radiation = 3x108 m/s
Therefore distance travelled in 30s = 30x3x108 = 9.0x109m
c) E = hv = hc/ λ = (6.626x10-34)(3.0x108) / (616x10-9 ) = 32.27x10-20J
d) No of quanta in 2J of energy = 2/32.27 x 10-28 = 6.2x1018
Following results are observed when sodium metal is irradiated with different wavelengths.
Calculate (a) threshold wavelength and, (b) Planck’s constant.
| λ (nm) | 500 | 450 |
400 |
| v × 10–5 (cm s–1) | 2.55 | 4.35 | 5.35 |
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 47: Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate (a) the ....
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Comments
Thqs for this answers
Thank you to Sò
Thanks for answering me
Velocity of radiation ko velocity of light kyo liya
Thanks for this extraordinary app â˺
Can you explain option (d) in detail
Nice
Thanks
Thanks
Frequency ma 10 ki power 16 kase ayi