(i) Calculate the total number of electr | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Current NCERT chapter

Academic session 2026-27, Chapter 2 in the current curriculum.

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Structure of Atom. This page offers a step-by-step solution to the specific question from Exercise 1, Question 2:

(i) Calculate the total number of electrons present in one mole of methane.

(ii) Find
(a) the total number and
(b) the total mass of neutrons in 7 mg of 14C. (Assume that mass of a neutron = 1.675 × 10–27 kg).

(iii) Find
(a) the total number and
(b) the total mass of protons in 34 mg of NH3 at STP.

Will the answer change if the temperature and pressure are chang

. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 2:

(i) Calculate the total number of electrons present in one mole of methane.

(ii) Find
(a) the total number and
(b) the total mass of neutrons in 7 mg of 14C. (Assume that mass of a neutron = 1.675 × 10–27 kg).

(iii) Find
(a) the total number and
(b) the total mass of protons in 34 mg of NH3 at STP.

Will the answer change if the temperature and pressure are chang

Answer:

(i) Molecule of CH4 (methane) contains electron = 10
Therefore 1 mole (6.022 x 1023 atoms) contains electron = 6.022 x 1024

(ii)  a) 1g atom of 14C = 14g = 6.022 x 1023 atoms = 6.022 x 1024 x 8 neutrons
Thus 14g or 14000 mg have 6.022 x 1024 x 8 neutrons
Therefore 7 mg will have neutrons = 6.022 x 1024 x 8 / 14000 x 7 = 2.4088 x 1022

b) mass of 1 neutron = 1.675 x 10-27 kg
Therefore mass of 2.4088 x 1021 neutrons = 2.4088 x 1021 x 1.67 x 10-27 = 4.0347 x 10-6 kg

(iii)  a) 1 mol of NH3 = 17g NH3 = 6.022 x 1023 molecules of NH3 = (6.022x1023)(7 + 3) proton = 6.022 x 1024 protons
Therefore 34 mg i.e 0.034 g NH3 = 6.022 x 1024 x 0.034/1 = 1.2044 x 1022 protons

b) mass of 1 proton = 1.6726 x 10-27 kg
Therefore mass of 1.2044 x 1022 protons = (1.6726 x 10-27)(1.2044 x 1022) kg = 2.0145 x 10-5 kg

No, the answer will not change with change in temperature & pressure.


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Structure of Atom.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • NTIGURA JEAN LUTHER
  • Nov 22, 2019

i need questions and answers of chemistry 11 edition


  • Alok upadhyay
  • Jul 26, 2019

Easy method helpfull


  • corrector
  • May 07, 2019

multiplication is wrong


  • Priyanshu jain
  • Jul 18, 2018

Easy to learn Very helpful


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 2: (i) Calculate the total number of electrons present in one mole of methane. (ii) Find (a) the to....

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