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Academic session 2026-27, Chapter 2 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Structure of Atom. This page offers a step-by-step solution to the specific question from Exercise 1, Question 5:
Yellow light emitted from a sodium lamp has a wavelength (λ) of 580 nm. Calculate the frequency (ν) and wave number (
) of the yellow light.
Yellow light emitted from a sodium lamp has a wavelength (λ) of 580 nm. Calculate the frequency (ν) and wave number (
) of the yellow light.
Here λ = 580 nm(given)
We have to find out ν & 
Therefore from the equation
we can write, 
Where, ν = frequency of yellow light
c = velocity of light in vacuum = 3 × 108 m/s
λ = wavelength of yellow light = 580 nm = 580 × 10–9 m
Substituting the values in
we get

Thus, frequency of yellow light emitted from the sodium lamp
= 5.17 × 1014 s–1
Wave number = it is defined as the number of wavelengths which can be accommodated in 1cm length along the direction of propagation.
Wave number of yellow light is given by the equation 
We have λ = 580 nm(given),putting the value in the equation
we get

Following results are observed when sodium metal is irradiated with different wavelengths.
Calculate (a) threshold wavelength and, (b) Planck’s constant.
| λ (nm) | 500 | 450 |
400 |
| v × 10–5 (cm s–1) | 2.55 | 4.35 | 5.35 |
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 5: Yellow light emitted from a sodium lamp has a wavelength (λ) of 580 nm. Calculate the frequen....
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Comments
Thanks
Thanks
Very usefull
How could you find out the sub shell by N=?
Thank you ...it is really usefull
It is very usefull
Thank you
Tq
Good Thanks a lot for this kind of help
Thanx it was useful