Class 10 Science - Chapter Electricity NCERT Solutions | An electric iron of resistance 20 &Omega

Welcome to the NCERT Solutions for Class 10th Science - Chapter Electricity. This page offers a step-by-step solution to the specific question from Excercise ".$ex_no." , Question 3: an electric iron of resistance 20 omega takes a....
Question 3

An electric iron of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30 s.

Answer

The amount of heat (H) produced is given by the joule’s law of heating as

H = VIt

Where,

Current, = 5 A

Time, t = 30 s

Voltage, = Current × Resistance = 5 × 20 = 100 V

H = 100 x 5 x 30 = 1.5x104 J

Therefore, the amount of heat developed in the electric iron is 1.5x104 J.

More Questions From Class 10 Science - Chapter Electricity

Write a Comment: