Class 10 Mathematics - Chapter Polynomials NCERT Solutions | On dividing x3 – 3x2 + x

Welcome to the NCERT Solutions for Class 10th Mathematics - Chapter Polynomials. This page offers a step-by-step solution to the specific question from Exercise 3, Question 4: on dividing x3 nbsp ndash 3x2 nbsp x 2 by a....
Question 4

On dividing x– 3x+ x + 2 by a polynomial g(x), the quotient and remainder were x – 2 nd –2x + 4, respectively. Find g(x).

Answer

                   Given  ,

                   Dividend  p(x) =  x3 - 3x2 + x + 2

                   Quotient = x – 2

                   Remainder = -2x + 4

             Let divisor  = g(x)

             As we know ,

             Dividend = Divisor × Quotient + Remainder

                      x3- 3x2 +x+ 2 = g(x) × (x – 2) + (-2x + 4)

                      x 3- 3x2 + x + 2 – (-2x + 4) = g(x) × (x – 2 )

                     Therefore, g(x) × (x – 2 ) = x3 – x2 + x + 2

       Now we will divide p(x) by quotient x – 2 to find divisor g(x)

                                

            Therefore ,  g(x) = ( x2 – x + 1 )

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