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Academic session 2026-27, Chapter 4 in the current curriculum.
Welcome to the NCERT Solutions for Class 9 Science - Chapter Motion. This page offers a step-by-step solution to the specific question from Exercise 0, Question 19:
An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height 100 m. What is the difference in their heights after 2 s if both the objects drop with same accelerations? How does the difference in heights vary with time?
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height 100 m. What is the difference in their heights after 2 s if both the objects drop with same accelerations? How does the difference in heights vary with time?
Initially, difference in heights of two objects
= 150 m – 100 m = 50 m
Distance travelled by first object in 2 s = h1
= 0 + ½ (2)2 = 2 g
Distance travelled by another object in 2 s = h2
= o + ½ (2)2 = 2 g
After 2 s, height at which the first object will be h1 = 150 - 2g
After 2 s, height at which the second object will be h2 = 100 - 2g
Thus, after 2 s, difference in height = 150 - 2g - (100 - 2g) = 50 m = initial difference in height.
Thus, the difference in height does not vary with time.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 0 , Question 19: An object is dropped from rest at a height of 150 m and simultaneously another object is dropped fro....
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