Find the (a) maximum frequency, and (b) | Class 12 Physics Chapter Dual Nature Of Radiation And Matter, Dual Nature Of Radiation And Matter NCERT Solutions

Welcome to the NCERT Solutions for Class 12 Physics - Chapter Dual Nature Of Radiation And Matter. This page offers a step-by-step solution to the specific question from Exercise 1, Question 1: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 1: Find the
(a) maximum frequency, and
(b) minimum wavelength of X-rays produced by 30 kV electrons.
Answer:

Potential of the electrons, V = 30 kV = 3 × 104 V

Hence, energy of the electrons, E = 3 × 104 eV

Where,

e = Charge on an electron = 1.6 × 10−19 C

 

(a)Maximum frequency produced by the X-rays = ν

The energy of the electrons is given by the relation:

E =

Where,

h = Planck’s constant = 6.626 × 10−34 Js

So  v = E / h

      = 1.6 x 10-19 x 3 x 104 / 6.626 x 10-34 = 7.24 x 1018 Hz

Hence, the maximum frequency of X-rays produced is 7.24 x 1018 Hz

 

(b)The minimum wavelength produced by the X-rays is given as:

λ = c / v

= 3 x 108 / 7.24 x 1018 = 4.14 x 10-11 m = 0.0414 nm

Hence, the minimum wavelength of X-rays produced is 0.0414 nm.


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Comments

  • Sp
  • Nov 10, 2018

instead of 104 read it 10^4


  • Jaseem
  • Sep 10, 2017

Answer should be hindi ok


  • Jaseem
  • Sep 10, 2017

BETTY


Add Comment

Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 1: Find the (a) maximum frequency, and (b) minimum wavelength of X-rays produced by 30 kV electrons.....