A rectangular wire loop of sides 8 cm an | Class 12 Physics Chapter Electromagnetic Induction, Electromagnetic Induction NCERT Solutions

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Academic session 2026-27, Chapter 6 in the current curriculum.

Welcome to the NCERT Solutions for Class 12 Physics - Chapter Electromagnetic Induction. This page offers a step-by-step solution to the specific question from Exercise 1, Question 1: A rectangular wire loop of sides 8 cm and 2 cm with a small cut is moving out of a region of uniform magnetic field of magnitude 0.3 T directed normal to the loop. What is the emf developed across the cut if the velocity of the loop is 1 cm s−1 in a direction normal to the
(a) longer side,
(b) shorter side of the loop? For how long does the induced voltage last in each case?. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 1: A rectangular wire loop of sides 8 cm and 2 cm with a small cut is moving out of a region of uniform magnetic field of magnitude 0.3 T directed normal to the loop. What is the emf developed across the cut if the velocity of the loop is 1 cm s−1 in a direction normal to the
(a) longer side,
(b) shorter side of the loop? For how long does the induced voltage last in each case?
Answer:

Length of the rectangular wire, l = 8 cm = 0.08 m

Width of the rectangular wire, b = 2 cm = 0.02 m

Hence, area of the rectangular loop,

A = lb

= 0.08 × 0.02

= 16 × 10−4 m2

Magnetic field strength, B = 0.3 T

Velocity of the loop, v = 1 cm/s = 0.01 m/s

(a) Emf developed in the loop is given as:

e = Blv

= 0.3 × 0.08 × 0.01 = 2.4 × 10−4 V

Time taken to travel along the width , t = Distance traveled / Velocity = b / v

                                                                    =  0.02 / 0.01 = 2 s

Hence, the induced voltage is 2.4 × 10−4 V which lasts for 2 s.

(b) Emf developed, e = Bbv

= 0.3 × 0.02 × 0.01 = 0.6 × 10−4 V

Time taken to travel along the length, t = Distance traveled / Velocity = l / v
                                                                     =  0.08 / 0.01 = 8 s

Hence, the induced voltage is 0.6 × 10−4 V which lasts for 8 s.


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Electromagnetic Induction.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • Pritam Shaw
  • Sep 26, 2019

❣️


  • Saba
  • Sep 04, 2019

Where I will get remaining questions of chapter electromagnetic induction.. please tell.


  • Debanjali Dey
  • Mar 07, 2015

Really helpful


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Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 1: A rectangular wire loop of sides 8 cm and 2 cm with a small cut is moving out of a region of uniform....

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