(a) Using the Bohr’s model calcula | Class 12 Physics Chapter Atoms, Atoms NCERT Solutions

Welcome to the NCERT Solutions for Class 12 Physics - Chapter Atoms. This page offers a step-by-step solution to the specific question from Exercise 1, Question 7: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 7:

(a) Using the Bohr’s model calculate the speed of the electron in a hydrogen atom in the n = 1, 2, and 3 levels.

 

(b) Calculate the orbital period in each of these levels.

Answer:

(a) Let ν1 be the orbital speed of the electron in a hydrogen atom in the ground state level, n1 = 1. For charge (e) of an electron, ν1 is given by the relation,

ν 1 = e2/n14πϵ0(h/2π) = e2/2ϵ0h

Where, e = 1.6 × 10−19 C

ϵ0 = Permittivity of free space = 8.85 × 10-12 N−1 C2 m−2

h = Planck’s constant = 6.62 × 10−34 Js

∴ ν1 = (1.6x10-19)2/2x8.85x10-12x6.62x10-34 = 0.0218 x 108 = 2.18 x 106 m/s

For level n2 = 2, we can write the relation for the corresponding orbital speed as:

ν2 = e2/n20h = (1.6x10-19)2/2x2x8.85x10-12x6.62x10-34 = 1.09 x 106 m/s

And, for n3 = 3, we can write the relation for the corresponding orbital speed as:

ν3 = e2/n30h = (1.6x10-19)2/3x2x8.85x10-12x6.62x10-34 = 7.27 x 105 m/s

Hence, the speed of the electron in a hydrogen atom in n = 1, n=2, and n=3 is 2.18 × 10 6 m/s, 1.09 × 10 6 m/s, 7.27 × 10 5 m/s respectively.

 

(b) Let T 1 be the orbital period of the electron when it is in level n1 = 1.

Orbital period is related to orbital speed as:

T1 = 2πr1 1

Where, r1 = Radius of the orbit

= n12h2ϵ0/πme2

h = Planck’s constant = 6.62 × 10−34 Js

e = Charge on an electron = 1.6 × 10−19 C

ϵ0 = Permittivity of free space = 8.85 × 10−12 N−1 C2 m−2

m = Mass of an electron = 9.1 × 10−31 kg

∴ T1 = 2πr11

= (2πx(1)2x(6.62x10-34)2x8.85x10-12)/2.18x106xπx9.1x10-31x(1.6x10-19)2

= 15.27x10-17 = 1.527x10-16 s

For level n 2 = 2, we can write the period as:

T2 = 2πr22

Where, r2 = Radius of the electron in n2 = 2

= (n2)2h2ϵ0/πme2

∴ T2 = 2πr22

= (2πx(2)2x(6.62x10-34)2x8.85x10-12)/1.09 x 106 x π x 9.1 x 10-31 x (1.6 x 10-19)2

= 1.22 x 10-15 s

And, for level n 3 = 3, we can write the period as:

T3 = 2πr33

Where, r 3 = Radius of the electron in n 3 = 3

= (n3)2h2ϵ0/πme2

∴ T3 = 2πr33

= (2πx(3)2x(6.62x10-34)2x8.85x10-12)/7.27 x 105 x π x 9.1 x 10-31 x (1.6 x 10-19)2

= 4.12 x 10-15 s

Hence, the orbital period in each of these levels is 1.52 × 10 −16 s, 1.22 × 10 −15 s, and 4.12 × 10 −15 s respectively.

 


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Atoms.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Latest Blog Posts

Stay updated with our latest educational content and study tips

Government Jobs by Age Limit: Eligibility and Opportunities in 2026

Government jobs continue to be one of the most popular employment options in India because of their job security, regular salary, pension benefits, and promotion prospects. However, one of the most frequent doubts of aspirants is age eligibility. Countless candidates are discouraged from applying for Government positions – or even from preparing for them – … Read more

Read More

NEET & JEE Preparation Guide for State Board Students

After preparation for NEET and JEE, students inclined towards studying under state education boards find themselves a step behind the CBSE students. The syllabus, question pattern and level of idea of these national entrance exams varies widely from most state board syllabus. But with the correct approach, students taking the state board can hold their … Read more

Read More

Simple and Compound Interest Formulas with Questions

Interest is one of the most significant ideas in maths and financial calculations. It is very common in banking, loan applications, investments, saving account and competitive exams. Simple Interest and Compound Interest make it easier to find out how much more is earned and/or paid on a principal during the period of time. These Interest … Read more

Read More

Spoken English Course Topics for Beginners in 2026

In 2026, students, professionals, and job seekers must have a high level of spoken English. Spoken English is a beginner level course to enhance learners’ communication skills in English, their pronunciation, vocabulary, grammar structure and confidence in speaking English fluently. Today, the emphasis of spoken English courses is placed on actual conversations, everyday speech practice … Read more

Read More

Add Comment

Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 7: (a) Using the Bohr’s model calculate the speed of the electron in a hydrogen atom in the n = 1....