A system has two charges qA = 2.5 × | Class 12 Physics Chapter Electric Charges and Field, Electric Charges and Field NCERT Solutions

Welcome to the NCERT Solutions for Class 12 Physics - Chapter Electric Charges and Field. This page offers a step-by-step solution to the specific question from Exercise 1, Question 9: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 9:

A system has two charges qA = 2.5 × 10−7 C and qB = −2.5 × 10−7 C located at points A: (0, 0, − 15 cm) and B: (0, 0, + 15 cm), respectively. What are the total charge and electric dipole moment of the system?

Answer:

According to the figure given below both the charges can be located in a coordinate frame of reference.

At A, amount of charge, qA = 2.5 × 10−7C (Given)

At B, amount of charge, qB = −2.5 × 10−7 C (Given)

Total charge of the system,

q = qA + qB = 2.5 × 10-7 C − 2.5 × 10−7 C = 0

Distance between two charges at points A and B,

d = 15 + 15 = 30 cm = 0.3 m

Electric dipole moment of the system is given by,

p = qA × d = qB × d = 2.5 × 10−7 × 0.3 = 7.5 × 10−8 C m along positive z-axis

Therefore, the electric dipole moment of the system is 7.5 × 10−8 C m along positive z−axis.


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  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Electric Charges and Field.
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Comments

  • saravanan
  • Jun 15, 2019

it is simple 15-(-15)=30 cm answer is 0.03 m


  • sneha
  • Jun 15, 2019

how to find distance in graph points?????????????????????????


  • Adriz
  • Dec 10, 2018

Exactly chaitanya


  • Chaitanya
  • Oct 21, 2017

The dipole must be along negative z axis


Add Comment

Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 9: A system has two charges qA = 2.5 × 10−7 C and qB = −2.5 × 10−7 C loca....