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Academic session 2026-27, Chapter 7 in the current curriculum.
Welcome to the NCERT Solutions for Class 12 Physics - Chapter Alternating Current. This page offers a step-by-step solution to the specific question from Exercise 1, Question 3:
A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in the circuit.
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in the circuit.
Inductance of inductor, L = 44 mH = 44 × 10-3 H
Supply voltage, V = 220V
Frequency, ν = 50Hz
Angular frequency, \[\begin{align}\omega = 2\pi v\end{align}\]
Inductive reactance, \begin{align}X_{L}= \omega L = 2\pi vL = 2\pi\times50\times44\times10^{-3} \Omega\end{align}
Rms value of current is given as:
\begin{align}I = \frac{v}{X_{L}}\end{align}
\begin{align} = \frac{220}{2\pi\times50\times44\times 10^{-3}} =15.92A\end{align}
Hence, the rms value of current in the circuit is 15.92 A.
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Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 3: A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in t....
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