Class 12th Physics 2018 Set2 Delhi Board Paper Solution
Using the concept of free electrons in a conductor, derive the expression for the conductivity of a wire in terms of number density and relaxation time. Hence obtain the relation between current density and the applied electric field E.
Consider a conductor of length L and cross sectional area A , when potental difference v is applied across its end the current produced is i. If n is the number of electrons per unit volume in conductor and Vd is the drift velocity then,
I = -nAeVd Equaltion 1.
Where e is charge on electron , n is no of density
Electric field produced at each point, E = V/L Equation 2
if t is relaxation time and e is the electric field strength then drift velocity
Vd = -etE / m Equation 3
Substituting value in equation 1:
I = - neA(-etE / m )
I = (n e2t / m ) AE Equation 4
As e = V/L then,
I = n e2t A / m x V/L
Or
V/I = m/n e2t x L/A
From other law R = V/I = m/n e2t x L/A Equation 5
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