Class 12th Physics 2017 Set2 Delhi Board Paper Solution

Question 26

A circular coil of cross-sectional area 200 cm2 and 20 turns is rotated about the vertical diameter with angular speed of 50 rad s−1 in a uniform magnetic field of magnitude 3.0 x 10 -2 T. Calculate the maximum value of the emf in the coil.

Answer

Given, area = 200 cm2 = 2 x  10-2 m2

Total number of turns,N = 20

Angular speed,ω = 50 rad s-1

Magnetic field =  3 x 10-2 T.

Maximum value of emf, emax  = n ABω

 =  20 x 200 x 10-4 x 3 x 10-2 x 50V

 = 4 x 3 x 5 x 10-2 V

 = 60 x 10-2 V = 0 6. V

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