Class 12th Physics 2017 Set2 Delhi Board Paper Solution
Draw a labelled diagram of AC generator. Derive the expression for the instantaneous value of the emf induced in the coil.
The labelled diagram of AC generator is as below:
Let at any moment t the perpendicular vector to the plane of coil makes angle θ with direction of magnetic field (B). So, flux passing through the coil
φ = Bcos θ. An
and θ = ωt
[ω is angular velocity of the coil]
So, φ = n A B cos ωt
If e is the instantaneous induced emf produced in the coil, then
Maximum value or peak value of e is attained when sin ωt = ± 1
∴ emax = nω AB
So, e = emax sin ωt
Since, the value of the sine function varies between +1and −1. So, the polarity of emf changes with time and also, output voltage is sinusoidal in nature.
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