Class 12th Physics 2017 Set1 Delhi Board Paper Solution

Question 21

For a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 2V. Given, the current amplification factor of the transistor is 100, find the input signal voltage and base current, if the base resistance is 1 kΩ.

Answer

Given Vce = 2V, Rc = 2kΩ , β = 100, R1 = 1kΩ,

We need to find

iB and VB 

ic = Collector current =   Vce  / Rc  = 2V / 2kΩ = 2V / 2 x10-3Ω = 1 x 10-3 A = 1.0mA

iB = base current      =   ic  /  β =  1.0m A / 100 = 0.01m A

iRB  = Input signal voltage  =  (0.01 mA) (1kΩ) = (0.01 x 10-3A) (1 x 103Ω) = 0.01V = 10mV 

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