Class 12th Chemistry 2017 Set3 Delhi Board Paper Solution

Question 9

Calculate the degree of dissociation (α) acetic acid if its molar conductivity (Λm) is 39.05 S cm2/mol-1

Given λ0H+ = 349.6 S cm2mol-1      and    λ0(CH3COO-) = 40.9 S cm2mol-1

 

Answer

The degree of dissociation is give by the following relation:

α  =  Λm / Λo

Where α is the degree of dissociation, Λm  is the molar conductivity and Λo  is the molar conductivity at infinite dilution.

We have given

λ0H+ = 349.6 S cm2mol-1 

and

λ0(CH3COO-) = 40.9 S cm2mol-1

then,

λ0CH3COOH  =  349.6 + 40.9 = 390.5


Now, degree of dissociation (α) is:

= 39.05 / 390.5

= 0.1

 

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